Difference between revisions of "Anhang - Test"
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7. backslash( \sqrt{1-e^2} backslash) ergibt: \( \sqrt{1-e^2} \) | 7. backslash( \sqrt{1-e^2} backslash) ergibt: \( \sqrt{1-e^2} \) | ||
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abc<u>A</u>uvw | abc<u>A</u>uvw | ||
</span> | </span> | ||
Schrödinger-Gleichung: | |||
$ \hat{H} = -\frac{\hbar^2}{2m} \frac{\partial^2}{\partial x^2} + \hat{V} $ | |||
<div> | <div> | ||
Latest revision as of 14:41, 15 October 2021
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1. :math: \sqrt{1-e^2} :/math: ergibt: [math]\displaystyle{ \sqrt{1-e^2} }[/math]
3. dollar \sqrt{1-e^2} dollar ergibt: $ \sqrt{1-e^2} $
4. dollardollar \sqrt{1-e^2} dollardollar ergibt: $$ \sqrt{1-e^2} $$
7. backslash( \sqrt{1-e^2} backslash) ergibt: \( \sqrt{1-e^2} \)
abcAuvw
abcAuvw
Schrödinger-Gleichung: $ \hat{H} = -\frac{\hbar^2}{2m} \frac{\partial^2}{\partial x^2} + \hat{V} $
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